Battle of Hanau order of battle

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At the 1813 Battle of Hanau, Napoleon’s French army defeated a much larger Austro-Bavarian force commanded by General Karl von Wrede. The Allied army numbered about 42,000 men (33,000 infantry, 9,000 cavalry) with 94 guns and was made up of two corps: Austrian and Bavarian.

- Austrian Corps: commanded by Field-Marshal-Lieutenant Baron Hennequin de Fresnel, about 24,000 men (18,000 infantry, 6,000 cavalry, 34 guns). It was organized into three divisions.
- Bavarian Corps: commanded by General Karl von Wrede, about 18,000 men (15,000 infantry, 3,000 cavalry, 60 guns). It consisted of two infantry divisions plus cavalry and artillery reserves.

French forces (outnumbered and retreating after Leipzig) had perhaps 30,000 men available, but not all were committed. At Hanau, only a portion of the Grande Armée fought:
- One division from Marshal Jacques MacDonald’s XIth Corps
- One division from Marshal Claude Victor’s IInd Corps
- The Imperial Guard infantry and artillery
- The Imperial Guard cavalry
- II Cavalry Corps about 3,000 men under General Horace François Sébastiani de La Porta

Guard units included:
- Imperial Guard infantry and artillery about 6,000 men under General Antoine Drouot
- Imperial Guard cavalry about 4,000 men under General Etienne de Nansouty