1918 Iowa gubernatorial election

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1918 Iowa gubernatorial election

The election was held on November 5, 1918. The Republican candidate William L. Harding, who was the incumbent, defeated the Democratic candidate Claude R. Porter with 50.55% of the vote.

Results
- William L. Harding (Republican) – 192,662 votes (50.55%)
- Claude R. Porter (Democratic) – 178,815 votes (46.92%)
- Andrew Engle (Socialist) – 8,005 votes (2.10%)
- M. L. Christian (Prohibition) – 1,625 votes (0.43%)

Harding’s victory kept the governorship in Republican hands.